Are there any O(1/n) algorithms?

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Are there any O(1/n) algorithms?

Or anything else which is less than O(1)?

32 Answers
32

This question isn’t as silly as it might seem to some. At least theoretically, something such as O(1/n) is completely sensible when we take the mathematical definition of the Big O notation:

Now you can easily substitute g(x) for 1/x … it’s obvious that the above definition still holds for some f.

For the purpose of estimating asymptotic run-time growth, this is less viable … a meaningful algorithm cannot get faster as the input grows. Sure, you can construct an arbitrary algorithm to fulfill this, e.g. the following one:

def get_faster(list):
    how_long = (1 / len(list)) * 100000
    sleep(how_long)

Clearly, this function spends less time as the input size grows … at least until some limit, enforced by the hardware (precision of the numbers, minimum of time that sleep can wait, time to process arguments etc.): this limit would then be a constant lower bound so in fact the above function still has runtime O(1).

But there are in fact real-world algorithms where the runtime can decrease (at least partially) when the input size increases. Note that these algorithms will not exhibit runtime behaviour below O(1), though. Still, they are interesting. For example, take the very simple text search algorithm by Horspool. Here, the expected runtime will decrease as the length of the search pattern increases (but increasing length of the haystack will once again increase runtime).

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