Bash if statement with multiple conditions throws an error

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I’m trying to write a script that will check two error flags, and in case one flag (or both) are changed it’ll echo– error happened. My script:

my_error_flag=0
my_error_flag_o=0
do something.....
if [[ "$my_error_flag"=="1" || "$my_error_flag_o"=="2" ] || [ "$my_error_flag"="1" &&     "$my_error_flag_o"="2" ]]; then
    echo "$my_error_flag"
else
    echo "no flag"
fi

Basically, it should be, something along:

if ((a=1 or b=2) or (a=1 and b=2))
  then
     display error
else
     no error
fi

The error I get is:

 line 26: conditional binary operator expected
 line 26: syntax error near `]'
 line 26: `if [[ "$my_error_flag"=="1" || "$my_error_flag_o"=="2" ] || [ "$my_error_flag"="1" && "$my_error_flag_o"="2" ]]; then'

Are my brackets messed up?

4 Answers
4

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