Arrow operator (->) in function heading

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I came across the following code:

template <typename T, typename T1> auto compose(T a, T1 b) -> decltype(a + b) {
   return a+b;
}

There is one thing I cannot understand:

Where could I find out what the arrow operator (->) means in the function heading?

I guess purely logically, that the -> operator determines a type, that auto will be deduced to, but I want to get this straight. I can’t find any information.

3 Answers
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