It appears that in PHP objects are passed by reference. Even assignment operators do not appear to be creating a copy of the Object.
Here’s a simple, contrived proof:
<?php
class A {
public $b;
}
function set_b($obj) { $obj->b = "after"; }
$a = new A();
$a->b = "before";
$c = $a; //i would especially expect this to create a copy.
set_b($a);
print $a->b; //i would expect this to show 'before'
print $c->b; //i would ESPECIALLY expect this to show 'before'
?>
In both print cases I am getting ‘after’
So, how do I pass $a to set_b() by value, not by reference?