Given a string file path such as /foo/fizzbuzz.bar
, how would I use bash to extract just the fizzbuzz
portion of said string?
14 Answers
Here’s how to do it with the # and % operators in Bash.
$ x="/foo/fizzbuzz.bar"
$ y=${x%.bar}
$ echo ${y##*/}
fizzbuzz
${x%.bar}
could also be ${x%.*}
to remove everything after a dot or ${x%%.*}
to remove everything after the first dot.
Example:
$ x="/foo/fizzbuzz.bar.quux"
$ y=${x%.*}
$ echo $y
/foo/fizzbuzz.bar
$ y=${x%%.*}
$ echo $y
/foo/fizzbuzz
Documentation can be found in the Bash manual. Look for ${parameter%word}
and ${parameter%%word}
trailing portion matching section.