Convert float to double without losing precision

It’s not that you’re actually getting extra precision – it’s that the float didn’t accurately represent the number you were aiming for originally. The double is representing the original float accurately; toString is showing the “extra” data which was already present.

For example (and these numbers aren’t right, I’m just making things up) suppose you had:

float f = 0.1F;
double d = f;

Then the value of f might be exactly 0.100000234523. d will have exactly the same value, but when you convert it to a string it will “trust” that it’s accurate to a higher precision, so won’t round off as early, and you’ll see the “extra digits” which were already there, but hidden from you.

When you convert to a string and back, you’re ending up with a double value which is closer to the string value than the original float was – but that’s only good if you really believe that the string value is what you really wanted.

Are you sure that float/double are the appropriate types to use here instead of BigDecimal? If you’re trying to use numbers which have precise decimal values (e.g. money), then BigDecimal is a more appropriate type IMO.

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