I cannot seem to figure out why i am getting this error
Math.java:6: error: ')' expected
if(args[1].equalsIgnoreCase("+")
^
Math.java:11: error: ')' expected
else if(args[1].equalsIgnoreCase("x")
^
Math.java:16: error: ')' expected
else if(args[1].equalsIgnoreCase("-")
^
Math.java:21: error: ')' expected
else if(args[1].equalsIgnoreCase("/")
^
4 errors
My code is
class Math
{
public static void main(String args[])
{
if(args[1].equalsIgnoreCase("+")
{
sum = Integer.parseInt(args[0]) + Integer.parseInt(args[2]);
System.out.println("The answere is : " + sum);
}
else if(args[1].equalsIgnoreCase("x")
{
sum = Integer.parseInt(args[0]) * Integer.parseInt(args[2]);
System.out.println("The answere is : " + sum);
}
else if(args[1].equalsIgnoreCase("-")
{
sum = Integer.parseInt(args[0]) - Integer.parseInt(args[2]);
System.out.println("The answere is : " + sum);
}
else if(args[1].equalsIgnoreCase("/")
{
sum = Integer.parseInt(args[0]) / Integer.parseInt(args[2]);
System.out.println("The answere is : " + sum);
}
else
{
System.out.println("Something seems to be wrong, please try again.");
}
}
}
When i try to enter the closing parenthesizes where it says they should go, it get more errors. Can anyone give me a brief description of what causes this error. I am simply trying to make a program that with do math, based on arguments entered into the command line when the program is run.
For example if i entered “java Math 1 + 1” It would solve that problem and spit out “The answere is 2.”
Any help you guys can offer on this would be greatly appreciated.