Let’s say I have an array of four objects:

var jsObjects = [
   {a: 1, b: 2}, 
   {a: 3, b: 4}, 
   {a: 5, b: 6}, 
   {a: 7, b: 8}
];

Is there a way that I can get the third object ({a: 5, b: 6}) by the value of the property b for example without a for...in loop?

17 s
17

Filter array of objects, which property matches value, returns array:

var result = jsObjects.filter(obj => {
  return obj.b === 6
})

See the MDN Docs on Array.prototype.filter()

const jsObjects = [
  {a: 1, b: 2}, 
  {a: 3, b: 4}, 
  {a: 5, b: 6}, 
  {a: 7, b: 8}
]

let result = jsObjects.filter(obj => {
  return obj.b === 6
})

console.log(result)

Find the value of the first element/object in the array, otherwise undefined is returned.

var result = jsObjects.find(obj => {
  return obj.b === 6
})

See the MDN Docs on Array.prototype.find()

const jsObjects = [
  {a: 1, b: 2}, 
  {a: 3, b: 4}, 
  {a: 5, b: 6}, 
  {a: 7, b: 8}
]

let result = jsObjects.find(obj => {
  return obj.b === 6
})

console.log(result)

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