How can I make grep print the lines below and above each matching line? [duplicate]

I have to parse a very large file and I want to use the command grep (or any other tool).

I want to search each log line for the word FAILED, then print the line above and below each matching line, as well as the matching line.

For example:

id : 15
Satus : SUCCESS
Message : no problem

id : 15
Satus : FAILED
Message : connection error

And I need to print:

id : 15
Satus : FAILED
Message : connection error