I need to convert a certain JSON string to a Java object. I am using Jackson for JSON handling. I have no control over the input JSON (I read from a web service). This is my input JSON:
{"wrapper":[{"id":"13","name":"Fred"}]}
Here is a simplified use case:
private void tryReading() {
String jsonStr = "{\"wrapper\"\:[{\"id\":\"13\",\"name\":\"Fred\"}]}";
ObjectMapper mapper = new ObjectMapper();
Wrapper wrapper = null;
try {
wrapper = mapper.readValue(jsonStr , Wrapper.class);
} catch (Exception e) {
e.printStackTrace();
}
System.out.println("wrapper = " + wrapper);
}
My entity class is:
public Class Student {
private String name;
private String id;
//getters & setters for name & id here
}
My Wrapper class is basically a container object to get my list of students:
public Class Wrapper {
private List<Student> students;
//getters & setters here
}
I keep getting this error and “wrapper” returns null
. I am not sure what’s missing. Can someone help please?
org.codehaus.jackson.map.exc.UnrecognizedPropertyException:
Unrecognized field "wrapper" (Class Wrapper), not marked as ignorable
at [Source: [email protected]; line: 1, column: 13]
(through reference chain: Wrapper["wrapper"])
at org.codehaus.jackson.map.exc.UnrecognizedPropertyException
.from(UnrecognizedPropertyException.java:53)