I want the following output:-
About to deduct 50% of € 27.59 from your Top-Up account.
when I do something like this:-
$variablesArray[0] = '€';
$variablesArray[1] = 27.59;
$stringWithVariables="About to deduct 50% of %s %s from your Top-Up account.";
echo vsprintf($stringWithVariables, $variablesArray);
But it gives me this error vsprintf() [function.vsprintf]: Too few arguments in ... because it considers the % in 50% also for replacement. How do I escape it?
