Show Specific Footer Widget for Specific Pages

by

I registered a new footer widget with this code.

register_sidebar(array(
  'name' => esc_html__( 'Footer Sidebarprestige', 'realtor' ),
  'id' => 'footer-sidebarprestige',
  'description' => esc_html__( 'Widgets in this area will be shown in Footer Area.', 'realtor' ),
  'class'=>'',
  'before_widget'=>'<li id="%1$s"  class="col-md-3 col-sm-6 widget %2$s">',
  'after_widget'=>'</li>',
  'before_title' => '<h5>',
  'after_title' => '</h5>'
));

I called it in my footer.php file like this:

<ul class="row">

   <?php dynamic_sidebar('footer-sidebar'); ?>

 </ul>

  <ul class="row">

   <?php dynamic_sidebar('footer-sidebarprestige'); ?>

 </ul>

The ‘footer-sidebar’ is original widget and the ‘footer-sidebarprestige’ is the one I added. The way it is now if I add a widget to the widget area I added it shows up under the original one and I understand why.

What I am trying to do. Call the widget area that I added only for certain page ID’s. Basically, only on called page ID’s show newly created footer widget and not show the original widget area.

3 Answers
3

There are several ways you can achieve this:

A. Use CSS to hide and show widgets based on which page you are on. This is fine as a workaround, but it isn’t really solving your problem, especially if you have lots of pages/widgets.

B. Call a different widget area in your template file with conditional logic

<ul class="row">
   <?php if(is_page('my-page')){
      dynamic_sidebar('footer-sidebarprestige');
   } ?> 
</ul>

C. Use a plugin like Widget Logic to use conditional logic on the widgets themselves. You can then add a condition like is_page('my-page') for displaying the widget, on a widget-per-widget basis.

Leave a Comment