I have an array that is initialized like: Element[] array = {new Element(1), new Element(2), new Element(3)}; I would like to convert this array into an object of the ArrayList class. ArrayList<Element> arraylist = ???; 3 39
String myString = “1234”; int foo = Integer.parseInt(myString); If you look at the Java documentation you’ll notice the “catch” is that this function can throw a NumberFormatException, which of course you have to handle: int foo; try { foo = Integer.parseInt(myString); } catch (NumberFormatException e) { foo = 0; } (This treatment defaults a malformed number to 0, but … Read more
You can use Character.toString(char). Note that this method simply returns a call to String.valueOf(char), which also works. As others have noted, string concatenation works as a shortcut as well: But this compiles down to: String s = new StringBuilder().append(“”).append(‘s’).toString(); which is less efficient because the StringBuilder is backed by a char[] (over-allocated by StringBuilder() to 16), only for that array to be defensively copied … Read more
You can use Double.parseDouble() to convert a String to a double: String text = “12.34”; // example String double value = Double.parseDouble(text); For your case it looks like you want: double total = Double.parseDouble(jlbTotal.getText()); double price = Double.parseDouble(jlbPrice.getText());
The ASCII table is arranged so that the value of the character ‘9’ is nine greater than the value of ‘0’; the value of the character ‘8’ is eight greater than the value of ‘0’; and so on. So you can get the int value of a decimal digit char by subtracting ‘0’. char x … Read more
Create ArrayList from array
Character.getNumericValue(c) The java.lang.Character.getNumericValue(char ch) returns the int value that the specified Unicode character represents. For example, the character ‘\u216C’ (the roman numeral fifty) will return an int with a value of 50. The letters A-Z in their uppercase (‘\u0041’ through ‘\u005A’), lowercase (‘\u0061’ through ‘\u007A’), and full width variant (‘\uFF21’ through ‘\uFF3A’ and ‘\uFF41’ through ‘\uFF5A’) forms have numeric values from 10 through 35. This … Read more
Convert an integer to an array of characters : java
What is the best possible way to check if a string can be represented as a number in Python? The function I currently have right now is: def is_number(s): try: float(s) return True except ValueError: return False Which, not only is ugly and slow, but also seems clunky. However, I haven’t found a better method … Read more
It looks like there’s an extra space character in your string. You can use trim() to remove leading and trailing whitespaces: temp1 = Integer.parseInt(display.getText().trim(), 16 ); Or if you think the presence of a space means there’s something else wrong, you’ll have to look into it yourself, since we don’t have the rest of your code.
