I use a for loop to iterate the string and use charAt() to get each character to examine it. Since the String is implemented with an array, the charAt() method is a constant time operation. String s = “…stuff…”; for (int i = 0; i < s.length(); i++){ char c = s.charAt(i); //Process char } That’s what I would … Read more
How can I check if a single character appears in a string?
String are immutable in Java. You can’t change them. You need to create a new string with the character replaced. String myName = “domanokz”; String newName = myName.substring(0,4)+’x’+myName.substring(5); Or you can use a StringBuilder: StringBuilder myName = new StringBuilder(“domanokz”); myName.setCharAt(4, ‘x’); System.out.println(myName);
I’m trying to replace a character at a specific index in a string. What I’m doing is: String myName = “domanokz”; myName.charAt(4) = ‘x’; This gives an error. Is there any method to do this? Best Answer String are immutable in Java. You can’t change them. You need to create a new string with the … Read more
